html - how to get href link from onclick function in python -

i want href link of website form onclick function here html code in onclick function call website

<div class="fl">    <span class="talnk" onclick="ta.trackeventonpage('eatery_listing', 'website', 594024, 1); ta.util.cookie.setpidcookie(15190); ta.call('ta.util.link.targetblank', event, this, {'ahref':'lqmwjqzzyuwjqpecygii26xombqqoqnqqqqoqnqgoqnqqqqoqnqqqqoqnqqqqoqnqgoqnqqqqoqnqquuuqqoqnqqqqoqnxioqnqqqqoqnqq2eissmvcnvcjqqoqnqqqqoqnxioqnqqqqoqnqqniaqqoqnqqqqoqnqgoqnqqqqoqnqqwjqzhymjkh3khvadjjh3vvdb', 'isasdf':true})">website</span>   </div>

normaly use code href link span or element

geturl = soup.findsoup("span", {"class": "talnk"})  link in geturl:    hreflink = link.get("href")    print(hreflink)

but in case there no way directly call href because href exist in onclick function

please me now

you cannot directly parse ahref attribute, need extract onclick first.

>>> import re >>> data = soup.select('.talnk')[0].get('onclick') >>> href = re.search(r"(?is)'ahref':'(.*?)'",str(data)).group(1) 'lqmwjqzzyuwjqpecygii26xombqqoqnqqqqoqnqgoqnqqqqoqnqqqqoqnqqqqoqnqgoqnqqqqoqnqquuuqqoqnqqqqoqnxioqnqqqqoqnqq2eissmvcnvcjqqoqnqqqqoqnxioqnqqqqoqnqqniaqqoqnqqqqoqnqgoqnqqqqoqnqqwjqzhymjkh3khvadjjh3vvdb'