c - scanf not reading mychars -

i'm making visual display pointers using table. first input length works mychars not being read. know there's new line after scanf don't know how behaves. how mychars's scanf parsed in particular case?

#include <stdio.h> #include <stdlib.h> #include <string.h>  int main() {     int length;     printf("length? ");     scanf("%d", &length);      char *mychars = (char *)calloc(length, sizeof(char));      printf("mychars? ");     scanf("%[^\n]s", mychars);     printf("mychars \"%s\"\n", mychars);     printf("pointer @ %p\n", mychars);     if (strlen(mychars) == length) {         printf("address    location        value\n");         int i;         (i = 0; < length; i++) {             printf("%-10p *(mychars+%02d) %3c\n", (mychars+i), i, *(mychars+i));         }     } else {         print("not right length");     }     free(mychars);     return 0; } 

do not use scanf(). evil. not handle problems , easy learners mis-use. use fgets().

// untested code int main(void) {   size_t length;  // use size_t array sizes   printf("length? ");   fflush(stdout); // insure prompt displayed before input.    char buf[50];   if (fgets(buf, sizeof buf, stdin) == null) return -1;   if (sscanf(buf, "%zu", &length) != 1) return -1;    char *mychars = malloc(length + 2);  // +1 \n, +1 \0   if (mychars == null) return -1;    printf("mychars? ");   fflush(stdout);   if (fgets(mychars, length + 2, stdin) == null) return -1;   // lop off potential \n   mychars[strcspn(mychars, "\n")] = 0;    printf("mychars \"%s\"\n", mychars);   printf("pointer @ %p\n", (void*) mychars);  // use `void *` %p    if (strlen(mychars) == length) {     printf("address    location        value\n");     size_t i;     (i = 0; < length; i++) {       printf("%-10p *(mychars+%02zu) %3c\n", (void*) (mychars + i), i, *(mychars + i));     }   } else {     printf("not right length\n");  // add \n   }   free(mychars);   return 0; }