Rerun code block in Python -

i looking try figure out way write this:

code_that_should_not_be_run_again() rerun_code_that_may_fail():   another_method(x)   run_me_again_if_i_fail(y) code_that_should_only_be_run_if_above_succeeds() 

where above run code, , catch exception, if caught, try run code, again. here longer version of want:

code_that_should_not_be_run_again() try:   another_method(x)   run_me_again_if_i_fail(y) catch exception:   try:     another_method(x)     run_me_again_if_i_fail(y)   catch exception:     raise exception("couldn't run")  code_that_should_only_be_run_if_above_succeeds() 

i thinking use generator, maybe catch yielded content in lambda , run twice, somehow, sure how can code this.

is possible in python? or maybe similar can done?

here's i've tried far:

from contextlib import contextmanager @contextmanager def run_code():     print 'will run'     try:       yield     except someexception:       try:         yield       except someexception:         raise someexception('couldn't run') 

edit python wont' let want do, can use decorators on functions :(

using retry decorator - https://pypi.python.org/pypi/retry/ - , under scenario want catch typeerror, maximum of 3 tries, delay of 5 seconds:

from retry import retry  @retry(typeerror, tries=3, delay=5) def code_block_that_may_fail():     method_1()     method_2()     #some more methods here...  code_block_that_may_fail() 

can't cleaner that.

additionally, can use built-in logger log failed attempts (see documentation).