c++ - Why gdb failed to print array elements? -

i wish use gdb print array elements of allocated memory.

int main() {    int* p=(int*)malloc(7*sizeof(int));     for(size_t j=0;j<7;++j) {          p[j]=j;     }     return 0;  }  

so compiled program -g3, use gdb start it, , set break

> print p@7  

i expected print out 1-7, actual output was

$1 = {0x6160b0, 0x5, 0xff00000000, 0x615c60, 0x615c80, 0x615c20, 0x615c40}  

why expectation!=actual result, wrong program?

the gdb manual says:

the left operand of `@' should first element of desired array , individual object. right operand should desired length of array. result array value elements of type of left argument

so if

 print p@7  

you tell gdb print array of 7 pointers.

what need is:

print *p@7